FairSharing is a collaborative tool designed for recording on-chain reputation and achieving automated distribution on-chain. The LXDAO PoC records have been fully implemented based on FairSharing.
FairSharing has currently registered over 50 projects, and in addition to LXDAO, external communities are also using it. It is hoped that FairSharing can be promoted to more communities in the future to make collaboration simpler. FairSharing is currently undergoing a new round of iteration to achieve a closed loop of collaboration and distribution, enhancing the level of automation and transparency in collaboration.
FairSharing official website: https://fairsharing.xyz/
Technology stack: Nextjs, Solidity, Database, Ethereum, EAS
Job openings: One front-end engineer + one back-end engineer or one full-stack engineer
Job requirements:
- We hope you are an experienced and responsible engineer with good team communication skills and the ability to collaborate efficiently with other members.
- We hope you have excellent visual reproduction capabilities.
- Have 10-15 hours per week to invest.
- Be familiar with the Ethereum ecosystem.
Salary: 20-25 LXPU/hour
To apply:
- Please reply to this post to sign up, introduce your development experience, and ideally provide a GitHub or other links where your code can be seen. You can also leave your Telegram for easy contact.
- Application deadline: November 3rd, 24:00 Beijing time.
- If you have any questions, you can contact Ray (tg: rayoo_eth).
FairSharing 是一个用于记录链上声誉并实现链上自动化分配的协作工具。LXDAO 的 PoC 记录已经完全基于 FairSharing 来实现。
FairSharing 目前已经注册了 50+ 的项目,目前除了 LXDAO 之外,也有外部的社区在使用,后续希望可以推广到更多的社区,让协作变得更简单。FairSharing 目前正在进行新一轮的迭代,让 FairSharing 实现协作+分配的闭环,提升协作的自动化程度及透明度。
FairSharing 官网:https://fairsharing.xyz/
技术栈:Nextjs、Solidity、数据库、以太坊、EAS
招聘数量:一名前端 + 一名后端或者一名全栈工程师
招聘要求:
- 希望你是一名有经验并且有责任心的工程师,具备良好的团队沟通能力,能够与其他成员高效协作
- 希望你有非常好的视觉还原能力
- 每周有 10~15 小时的时间投入
- 对以太坊生态熟悉
薪资 :20-25 LXPU/hour
报名:
- 请在帖子回复报名,介绍一下自己的开发经验,最好可以有 GitHub 或其他可以看到你写过的代码的链接,可以留一下自己的 telegram,方便联系
- 报名截止时间:北京时间 11 月 3 日晚 24 点
- 有任何问题可以联系 Ray(tg: rayoo_eth)